获取基本文件名

1 2	filename="/tmp/test.txt" os.path.basename(filename)

获取基本文件名(不包括拓展名)

1 2	filename="/tmp/test.txt" os.path.splitext(os.path.basename(filename))[0]

获取文件拓展名

1 2	filename="/tmp/test.txt" os.path.splitext(os.path.basename(filename))[1]

获取父目录

1 2	filename="/tmp/test.txt" os.path.dirname(filename)

参考

http://stackoverflow.com/questions/678236/how-to-get-the-filename-without-the-extension-from-a-path-in-python

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